Additional informations from Sergey M.Godin (10-25-98)

A thermo-converter in my latest test had measured real effective value of a pulsed current. By other words I had measured THE PURE ACTIVE POWER dissipated on Rload during charge/discharge process.

(P=R*I^2 as Rload =4+1ohm is full active).

Where is the Joule losses in this test?

This losses are fully account into Charge/Discharge process.

For example:

• Vdischarge=1.31mV--->effective current=127.5mA-->P=0.081W
• Vcharge = 0.97mV--->effective current=108.8mA-->P=0.059W
• Power Gain =37% !!!!